Lebesgue積分講義ノート

4.2. 基本性質🔗

Proposition4.2.1
uses 1used by 1L∃∀N

任意の A,B \subset \RR^d に対して次が成り立つ.

  • 0 \le \lambda_*(A) \le \lambda^*(A)

  • A \subset B ならば \lambda_*(A) \le \lambda_*(B)

Lean code for Proposition4.2.13 theorems
  • theoremdefined in NoteKsk/«04lebesgue-inner».lean
    complete
    theorem NoteKsk.Chapter04.lambdaInner_nonneg {d : }
      (A : Set (NoteKsk.Space d)) : 0  NoteKsk.Chapter04.lambdaInner A
    theorem NoteKsk.Chapter04.lambdaInner_nonneg
      {d : } (A : Set (NoteKsk.Space d)) :
      0  NoteKsk.Chapter04.lambdaInner A
  • theoremdefined in NoteKsk/«04lebesgue-inner».lean
    complete
    theorem NoteKsk.Chapter04.lambdaInner_le_lambdaStar {d : }
      (A : Set (NoteKsk.Space d)) :
      NoteKsk.Chapter04.lambdaInner A  NoteKsk.Chapter03.lambdaStar A
    theorem NoteKsk.Chapter04.lambdaInner_le_lambdaStar
      {d : } (A : Set (NoteKsk.Space d)) :
      NoteKsk.Chapter04.lambdaInner A 
        NoteKsk.Chapter03.lambdaStar A
  • theoremdefined in NoteKsk/«04lebesgue-inner».lean
    complete
    theorem NoteKsk.Chapter04.lambdaInner_mono {d : } {A B : Set (NoteKsk.Space d)}
      (hAB : A  B) :
      NoteKsk.Chapter04.lambdaInner A  NoteKsk.Chapter04.lambdaInner B
    theorem NoteKsk.Chapter04.lambdaInner_mono {d : }
      {A B : Set (NoteKsk.Space d)}
      (hAB : A  B) :
      NoteKsk.Chapter04.lambdaInner A 
        NoteKsk.Chapter04.lambdaInner B
Proof for Proposition 4.2.1
uses 0
  • コンパクト集合 K \subset A に対して,外測度の単調性より

\lambda^*(K) \le \lambda^*(A)

である. 左辺について上限を取れば

\lambda_*(A) \le \lambda^*(A)

を得る. また外測度は常に非負なので,その上限である \lambda_*(A) も非負である.

  • A \subset B とする. K \subset A なる任意のコンパクト集合は,そのまま K \subset B も満たす. したがって,A に対して取る上限は B に対して取る上限以下である.

Proposition4.2.2
uses 1
Used by 2
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Theorem 4.4.1
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L∃∀N

コンパクト集合では内外が一致する. コンパクト集合 K \subset \RR^d に対して

\lambda_*(K)=\lambda^*(K)

が成り立つ.

Lean code for Proposition4.2.22 theorems
  • theoremdefined in NoteKsk/«04lebesgue-inner».lean
    complete
    theorem NoteKsk.Chapter04.lambdaInner_eq_lambdaStar_of_isCompact {d : }
      {K : Set (NoteKsk.Space d)} (hK : IsCompact K) :
      NoteKsk.Chapter04.lambdaInner K = NoteKsk.Chapter03.lambdaStar K
    theorem NoteKsk.Chapter04.lambdaInner_eq_lambdaStar_of_isCompact
      {d : } {K : Set (NoteKsk.Space d)}
      (hK : IsCompact K) :
      NoteKsk.Chapter04.lambdaInner K =
        NoteKsk.Chapter03.lambdaStar K
    Compact sets have equal inner and outer measure. 
  • theoremdefined in NoteKsk/«04lebesgue-inner».lean
    complete
    theorem NoteKsk.Chapter04.lambdaInner_eq_zero_of_lambdaStar_eq_zero {d : }
      {A : Set (NoteKsk.Space d)}
      (hA : NoteKsk.Chapter03.lambdaStar A = 0) :
      NoteKsk.Chapter04.lambdaInner A = 0
    theorem NoteKsk.Chapter04.lambdaInner_eq_zero_of_lambdaStar_eq_zero
      {d : } {A : Set (NoteKsk.Space d)}
      (hA :
        NoteKsk.Chapter03.lambdaStar A = 0) :
      NoteKsk.Chapter04.lambdaInner A = 0
    A set of outer measure zero has inner measure zero. 
Proof for Proposition 4.2.2
uses 0

K 自身がコンパクトだから, 内測度の上限を取る集合の中に K そのものが含まれている. したがって

\lambda_*(K) \ge \lambda^*(K)

である. 逆向きの不等式は前命題から従う.

Corollary4.2.3
uses 0used by 0XL∃∀N

外測度零集合の内測度. \lambda^*(A)=0 ならば

\lambda_*(A)=0

である.

Proof for Corollary 4.2.3
uses 0

基本性質の (1) より

0 \le \lambda_*(A) \le \lambda^*(A)=0

だからである.